Second Equation of Motion


 
 
Concept Explanation
 

Second Equation of Motion

SECOND EQUATION OF MOTION:

large s=ut+frac{1}{2}at^{2}

Displacement = initial velocity large times large frac{1}{2}  large times acceleration large times  large time;interval^{2}

Distance travelled = average velocity large times time = large left ( frac{Initial;velocity+final;velocity}{2} right )times time

    or   large s=frac{u+v}{2}times t

But from eq. (1), v = u + at

        large therefore   large s=frac{u+(u+at)}{2}times t      or     large s=frac{2u+at}{2}times t

    or   large s=ut+frac{1}{2}at^{2}

Sample Questions
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Question : 1

A particle starts moving from rest with uniform acceleration. It travels a distance X in the first tthree second and a distance Y in next three seconds, then:

Right Option : B
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Question : 2

A bus starts moving with acceleration 2 m/small S^2 .A cyclist 96 m behind the bus starts simultaneously towards the bus at 20 m/s. After what time will he be able to overtake the bus?

Right Option : B
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Question : 3

A body starts moving with an initial velocity of  4;m;s^-^1 and an acceleration of x;m;s^-^2 If the distance travelled by it is 30 m in 2^n^d s, then the value of x is ______ .

Right Option : D
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Explanation
 
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